8x^2=36x+140

Solution for 8x^2=36x+140 equation:

8x^2=36x+140

We move all terms to the left:

8x^2-(36x+140)=0

We get rid of parentheses

8x^2-36x-140=0

a = 8; b = -36; c = -140;
Δ = b2-4ac
Δ = -362-4·8·(-140)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-76}{2*8}=\frac{-40}{16}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+76}{2*8}=\frac{112}{16}
=7
$